4-2y^2/7=2y

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Solution for 4-2y^2/7=2y equation: 


y in (-oo:+oo)

4-((2*y^2)/7) = 2*y // - 2*y

4-((2*y^2)/7)-(2*y) = 0

(-2/7)*y^2-2*y+4 = 0

4-2/7*y^2-2*y = 0

DELTA = (-2)^2-(-2/7*4*4)

DELTA = 60/7

DELTA > 0

y = ((60/7)^(1/2)+2)/(-2/7*2) or y = (2-(60/7)^(1/2))/(-2/7*2)

y = -7/4*((60/7)^(1/2)+2) or y = -7/4*(2-(60/7)^(1/2))

y in { -7/4*((60/7)^(1/2)+2), -7/4*(2-(60/7)^(1/2)) }

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